Question

Find two numbers whose sum is 64 and whose difference is 16.

Answer 1

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$lets \: fjrst \: number \: is \: = x \\ difference \: between \: two \: number = 16 \\ the \: second \: number \: = x - 16 \\ according \: to \: sum = \\ x + x + 16 = 64\\ 2x +16 = 64 \\ 2x = 64 - 16 \\ 2x = 48 \\ x = 48 \div 2 \\ x = 24 \\ \\ frst \: number \: x = 24 \\ second \: number = x + 16 = 24 + 16 = 40$

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