Find two numbers whose sum is 8 and whose product is a maximum in application of derivative
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Given : Two numbers sum is 8 and product is a maximum
To Find : Two numbers
Solution:
Two numbers sum is 8
One number is x
Then other number is 8 - x
Product = x(8 - x)
P(x) = 8x - x²
Taking derivative
P'(x) = 8 - 2x
P'(x) = 0
8 - 2x = 0
=> x = 4
p''(x) = - 2 < 0
Hence product is maximum at x = 4
x = 4 => 8 - x = 4
Hence both the numbers are 4 and 4
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