Math, asked by mou40, 1 year ago

Find two numbers whose sum shall be 26 and there differences is 8​

Answers

Answered by Akashmaury
2

Answer:

Let first number is x

second number is 26-x

and there difference is 8

so, 26-x -x = 8

=. 26-2x = 8

=. -2x = 8 - 26

.-2x = -18

.= x. = -18/-2 = 9

x = 9

and second number is 26 -x

26 - 9 = 17


Meewaw: But isn't 15+9 = 24 not 26 and 15-9 = 6
Meewaw: I guess the answer is wrong
mou40: so what's the correct answer is?
Akashmaury: correct answer is 9 and 17
mou40: ans my another question...which i have jst sent
Akashmaury: ok please give me brainliest
Akashmaury: for next level
Answered by Meewaw
0

Answer:

9 and 17

Step-by-step explanation:

Let one number be 'a' and the other be 'b'.

Sum of the numbers,

a + b = 26

Difference,

a - b = 8

Solving both equations

a + b = 26

a - b = 8

_________

2a     = 34        ⇒ a = 17

_________

Substituting a = 17 in a + b = 26,

17 + b = 26

b = 26 - 17

b = 9

∴ One number is 9 and the other is 17.

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