Find two numbers whose sum shall be 26 and there differences is 8
Answers
Answered by
2
Answer:
Let first number is x
second number is 26-x
and there difference is 8
so, 26-x -x = 8
=. 26-2x = 8
=. -2x = 8 - 26
.-2x = -18
.= x. = -18/-2 = 9
x = 9
and second number is 26 -x
26 - 9 = 17
Meewaw:
But isn't 15+9 = 24 not 26 and 15-9 = 6
Answered by
0
Answer:
9 and 17
Step-by-step explanation:
Let one number be 'a' and the other be 'b'.
Sum of the numbers,
a + b = 26
Difference,
a - b = 8
Solving both equations
a + b = 26
a - b = 8
_________
2a = 34 ⇒ a = 17
_________
Substituting a = 17 in a + b = 26,
17 + b = 26
b = 26 - 17
b = 9
∴ One number is 9 and the other is 17.
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