Math, asked by sally201005, 9 months ago

Find two numbers with a sum of 15 and a difference of 3.

Answers

Answered by leonkaushikdeka
2

Answer:

9 and 6

Step-by-step explanation:

Let the two different numbers be X and y respt.

A/Q,

X+Y=15 and X-Y=3

Let the two statements be considered as equations 1 and 2 respt.

Adding both the equations, we get

2X=18

=>X=9 and putting X=9 in eq 1, we get Y= 6

Therefore, the two required numbers are 9 and 6 respt.

Answered by iamharidasmk
2

Answer

9 and 6

Step-by-step explanation:

Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 15. In other words, x plus y equals 15 and can be written as equation A:

x + y = 15

The difference between x and y is 3. In other words, x minus y equals 3 and can be written as equation B:

x - y = 3

Now solve equation B for x to get the revised equation B:

x - y = 3

x = 3 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 15

3 + y + y = 15

3 + 2y = 15

2y = 12

y = 6

Now we know y is 6. Which means that we can substitute y for 6 in equation A and solve for x:

x + y = 15

x + 6 = 15

X = 9

Answer: 9 and 6 as proven here:

Sum: 9 + 6 = 15

Difference: 9 - 6 = 3

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