Question

find two parts of 15 such that the sum of their reciprocals is 3/10​

Answer 1

Step-by-step explanation:

first condition

x+y=15____(1)

by second condition

1/x + 1/y = 3/10

3x + 3y =10____(2)

multiply equation (1) by 3

3x+3y = 45____(3)

add and subtract equation (2) & (3)

addition: 6x+6y = 55___(4)

subtraction :o=35_____(5)

add (4)&(5)

6x+6y = 90

Answer 2

✍️A᭄NSWER✍️

ʟᴇᴛ ᴛʜᴇ ᴛᴡᴏ ᴘᴀʀᴛs ʙᴇ x ᴀɴᴅ x − 15.

$\frac{1}{x} + \frac{1}{15 - x} = \frac{3}{10}$

$\frac{15 - x + x}{x(15 - x} = \frac{3}{10}$

$\frac{15}{15x - {x}^{2} } \ = \frac{3}{10}$

➪ 150 = 145 - 3x^2

➪ 3x^2 - 45x + 150 = 0

➪ x^2 - 15x + 150 = 0

➪ (x-5) (x-10)

➪ x = 5 , 10

x = 5

⟹ ᴏɴᴇ ᴘᴀʀᴛ = 5 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 10 x = 10

⟹ ᴏɴᴇ ᴘᴀʀᴛ = 10 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 5 ᴛʜᴜs,

ᴛʜᴇ ʀᴇǫᴜɪʀᴇᴅ ᴛᴡᴏ ᴘᴀʀᴛs ᴀʀᴇ 5 ᴀɴᴅ 10.

╚─━━━━━░★░━━━━━─╝