Question

find two parts of 40 such that the sum of their squares is 850

Answer 1

let the two parts = x, 40-x
x^2 + (40-x)^2 = 850
x^2 + 1600 -80x +x^2 = 850
2x^2 -80x +1600 = 850
x^2 -40x + 800 = 425
x^2 -40x +375 = 0
solve the quadratic equation, you'll get x, the first number. the second number is 40-x

Answer 2

25 and 15 are the answers