find two positive numbers
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1
Step-by-step explanation:
let the numbers be x and y and x > y
given x + y = 12 and x² - y² = 48
x² - y² = (x + y)(x - y)
=> 48 = 12 × (x - y)
=> x - y = 4
now x + y = 12
x - y = 4
2x = 16 => x = 8 and 8 + y = 12 => y = 4
therefore two positive numbers are 8 and 4
Answered by
2
Answer:
Since sum of the numbers is 12, the two numbers are x and 12-x
By the question:
x^2- (12-x)^2 = 48
x^2-144-x^2+24x= 48
24x= 144+48
24x= 192
x= 192/24
x= 8
The two numbers are 8 and 4
Step-by-step explanation:
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