find two positive numbers in the ratio 2:5 such that their difference is 15
Answers
Answered by
16
here is your answer
as you have said that number is in ratio of 2 : 5
so we can say that the numbers are 2x and 5x
and difference of these number is 15
so according to question
5x > 2x
so 5x - 2x = 15
= 3x = 15
5 = x
so first positive number is 2x = 2×5 = 10
and other number is 5x = 5×5 = 25
please mark me as brainliast
please...............
as you have said that number is in ratio of 2 : 5
so we can say that the numbers are 2x and 5x
and difference of these number is 15
so according to question
5x > 2x
so 5x - 2x = 15
= 3x = 15
5 = x
so first positive number is 2x = 2×5 = 10
and other number is 5x = 5×5 = 25
please mark me as brainliast
please...............
Anuj3105:
is it right
Answered by
3
Let the tow positive number be 2x and 5x.
Difference = 15
A.T.O.
2x-5x = 15
-3x = 15
x = 15/-3
x = -5
Then, 2x= -10 and
5x = -25
Hence,
-10-(-25)=15
-10+25=15
15=15
Hence Proved.....
Difference = 15
A.T.O.
2x-5x = 15
-3x = 15
x = 15/-3
x = -5
Then, 2x= -10 and
5x = -25
Hence,
-10-(-25)=15
-10+25=15
15=15
Hence Proved.....
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