find two positive numbers which have a difference of 5 and whose product is 84
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Answered by
52
Let the Numbers be x and y respectively
According to the given question
xy = 84
x = 84/y ----------------1
x - y= 5 ----------------2
Substituting The Value of x in equation 2
x - y = 5
84 - y = 5
----
y
84 - y² = 5
--------
y
84 - y² = 5y
y² + 5y - 84 = 0
y² - 7y + 12y - 84 = 0
y(y - 7) + 12(y - 7) = 0
(y - 7)(y +12) = 0
y = 7 or y = -12
In the Question it is Specified that the numbers are positive so y can be negative
So,
y = 7
Substitute the value of y In Equation 2
x - y = 5
x - 7 = 5
x = 12
Therefore
The Numbers are 12 and 7
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According to the given question
xy = 84
x = 84/y ----------------1
x - y= 5 ----------------2
Substituting The Value of x in equation 2
x - y = 5
84 - y = 5
----
y
84 - y² = 5
--------
y
84 - y² = 5y
y² + 5y - 84 = 0
y² - 7y + 12y - 84 = 0
y(y - 7) + 12(y - 7) = 0
(y - 7)(y +12) = 0
y = 7 or y = -12
In the Question it is Specified that the numbers are positive so y can be negative
So,
y = 7
Substitute the value of y In Equation 2
x - y = 5
x - 7 = 5
x = 12
Therefore
The Numbers are 12 and 7
Mark this Brainliest if this Helped u
RUTVI1:
7 and 12 is the answer
7 and 12 is the answer
Ohhh ya i found the right answer but wrote the wrong answer in the statement
But now i have edited it
thanks for editing
Thankx for making me realize
it ok practice makes man perfect
Answered by
3
12*7=84
12-7=5
here is ur answer
12-7=5
here is ur answer
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