find two positive numbers whose squares have a difference 48 and the sum of the numbers is 12
Answers
Answered by
31
sum of the numbers =12
let the 1st number will be x
then 2nd number will be 12-x
square of numbers have a difference = 48
=>(x^2)-(12-x)=48
=>x^2-12+x =48
=> x^2+x+36=0
we have a quadratic equation u solve it by middle term splitting and quadratic formula
let the 1st number will be x
then 2nd number will be 12-x
square of numbers have a difference = 48
=>(x^2)-(12-x)=48
=>x^2-12+x =48
=> x^2+x+36=0
we have a quadratic equation u solve it by middle term splitting and quadratic formula
Similar questions