Find two positive numbers whose sum is 16 and the sum of cubes of them is minimum.
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0
Answer:
https://www.teachoo.com/4411/712/Ex-6.5--16---Find-two-positive-numbers-whose-sum-is-16/category/Ex-6.5/
Step-by-step explanation:
Answered by
1
Two numbers are 8 and 8.
Step-by-step explanation:
Let's assume that the two numbers are x and y
Given that x + y = 16, we get y = 16 - x
Sum S = x^2 + y^2
= x^2 + (16-x)^2
= x^2 + 256 + x^2 - 32x
= 2x^2 - 32x + 256
dS/dx = 4x - 32
For the sum to be minimum, dS/dx = 0
4x - 32 = 0
4x = 32
x = 8
y = 16-x
Substituting the x value we just found, we get y = 16-8 = 8
So, the two numbers are 8 and 8.
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