Question

find two positive numbers whose sum is 8 and sum of their squares is minimum​

Answer 1

Answer:7/2

Step-by-step explanation:

let the two positive numbers be x,x+1

where as x>0

x+x+1=8

2x+1=8

x=7/2

Answer 2

Answer:

Let numbers are x and y. <br>

…(1) <br> Let the sum of cubes of two number be S. <br>

<br>

[From eq. (1)] <br>

<br>

<br> For maxima/minima <br>

<br>

<br>

<br> Now

<br>

S is minimum at x = 4 <br>

<br> Therefore, the required number are 4, 4.