Question

find two rational number 1and 2 using mean method​

Answer 1

Step-by-step explanation:

Question:

To find 2 rational number lying betweenx1 and 2 by using mean method.

Explaination:

$\sf \: \frac{1}{2} (1 + 2) \\</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> \sf \: \frac{1}{2} \times 3 \\</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> \sf \: \frac{3}{2} \\ \\ \sf \: 1st \: rational \: number \: is \: \frac{3}{2}$

$\sf \: \frac{1}{2}( \frac{3}{2} + 2) \\ </strong><strong>\</strong><strong>\</strong><strong> \sf \: \frac{1}{2} ( \frac{3 + 4}{2} \\</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> \sf \: \frac{1}{2} \times \frac{7}{2} \\ </strong><strong>\</strong><strong>\</strong><strong> \sf \: \frac{7}{4}$

Answer 2

Answer:

4/3 , 5/3

Working rule :

★ Let the smaller number be x and greater number be y .

★ Then find the common difference d using the formula ; d = (y - x)/(n +1) , where n is the number of Rational numbers to be found between x and y .

★ The the required rational numbers will be given as ;

1st rational no. = x + d

2nd rational no. = x + 2d

3rd rational no. = x + 3d

:

:

nth rational no. = x + nd

Solution:

Here,

We need to find two rational numbers between 1 and 2 .

Thus,

x = 1 , y = 2 , n = 2

Now,

=> d = (y - x)/(n + 1)

=> d = (2 - 1) / (2 + 1)

=> d = 1/3

Thus,

The required rational numbers will be ;

• 1st rational number = x + d

= 1+ 1/3

= (3 + 1)/3

= 4/3

• 2nd rational number = x + 2d

= 1/4 + 2/3

= (3 + 2)/3

= 5/3

Hence,

The required rational numbers are :

4/3 , 5/3