Find two rational number s of the form p/q between the numbers 0.2121121112... and 0.2020020002...
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Answers
Answered by
15
hlo...
here the ans is..
__
0.2121121112=0.21
let the x be 0.21
x=0.21 --------equ 1
since the periodicity are 2 ,multiply the equ 1 with 100
__
100× x =100×0.21 __
100x = 100×0.2121
__
100x =21.21 ------ equ 2
solving equ 1 and 2
__
100x =21.21
__
x= 0.21
_______________
99x = 21
x=21/99
x=7/33
__
2 sol ) 0.2020020002....=0.20
let the x be 0.20 ---- equ 1
sinc the periodicity are 2 multiply equ 1 with 100...
__
100x = 100×0.20
__
100x = 100×0.2020
__
100x =20.20 ----equ 2
solving equ 1 and 2
__
100x =20.20
__
x = 0.20
__________
99x = 20
x=20/99
hope my ans helps u buddy.....
^-^
plz.....make my ans brainliest if i deserve
here the ans is..
__
0.2121121112=0.21
let the x be 0.21
x=0.21 --------equ 1
since the periodicity are 2 ,multiply the equ 1 with 100
__
100× x =100×0.21 __
100x = 100×0.2121
__
100x =21.21 ------ equ 2
solving equ 1 and 2
__
100x =21.21
__
x= 0.21
_______________
99x = 21
x=21/99
x=7/33
__
2 sol ) 0.2020020002....=0.20
let the x be 0.20 ---- equ 1
sinc the periodicity are 2 multiply equ 1 with 100...
__
100x = 100×0.20
__
100x = 100×0.2020
__
100x =20.20 ----equ 2
solving equ 1 and 2
__
100x =20.20
__
x = 0.20
__________
99x = 20
x=20/99
hope my ans helps u buddy.....
^-^
plz.....make my ans brainliest if i deserve
Answered by
7
hope it helps... please mark it as BRAINLIST if it is right..
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