Find two rational numbers which differ by 3 and the sum of whose squares is 117
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The two rational numbers are -6&-9 or 6&9
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Answer:
Answer: -6,-9 or 6,9
Step-by-step explanation:
Let the numbers be x and x-3
Then,
x^2+(x-3)^2=117
x^2+x^2+9-6x=117
2x^2-6x-108=0
x^2-3x-54=0
x^2-9x+6x-54=0
x(x-9)+6(x-9)=0
(x-9)=0 or (x+6)=0
x=9 or x= -6
Difference:-
x=9
y=9-3
=6
or
x= -6
y= -6-3
= -9
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