find two solution for the equation 3y+4=0
Answers
Answered by
251
Hey user here's ur answer :-)
As there is no x in the given equation so we will add here
o+3y+4=0
0x+3y+4=0
now
♦ For x=0
0(0)+3y+4=0
3y=-4
y=-4/3
so (0,-4/3) is a solution
♦ For x=1
0(1)+3y+4=0
0+3y+4=0
3y=-4
y=-4/3
so (1,-4/3) is a solution
hope it helps
As there is no x in the given equation so we will add here
o+3y+4=0
0x+3y+4=0
now
♦ For x=0
0(0)+3y+4=0
3y=-4
y=-4/3
so (0,-4/3) is a solution
♦ For x=1
0(1)+3y+4=0
0+3y+4=0
3y=-4
y=-4/3
so (1,-4/3) is a solution
hope it helps
Answered by
10
Given: Here we have the equation 3y+5=0
To find: we have to find two solution for the equation
Solution:
Here we will consider x=0
0x+3y+4=0
0.x +3y+4=0
3y=-4
y=-4/3
Here we get the first solution when x is 0 then y is -4/3
Here we will consider x=1
0x+3y+4=o
0(1)+3y+4=0
3y=-4
y=-4/3
(1,-4/3)
Here we get the second solution when x is 1 then y is -4/3
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