Find two solution of each of the following equations : (i) 4x+3y=12
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4x+3y=12
At x=0
0+3y=12
y=12÷3=4
At y=0
4x+0=12
x=12÷4=3
Two solutions are (0,4). and. (3,0)
At x=0
0+3y=12
y=12÷3=4
At y=0
4x+0=12
x=12÷4=3
Two solutions are (0,4). and. (3,0)
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