Math, asked by mansi313, 1 year ago

find two solution of the equation 4x-5y=15. also check wheather(2,-2) is a solution or not. answer plz. or i make brainly.

Answers

Answered by veergermany025
32

Answer:

Two solutions are (5,1) , (10,5)

and (2,-2) is not a solution of the given equation.

Step-by-step explanation:

Given 4x-5y=15

so 4x=15+5y

hence x=(5y+15)/4

for y=1

x=(5+15)/4=20/4=5

and for y=5

x=(25+15)/4=40/4=10

hence two solutions are (5,1) and (10,5)

lets substitute

y= -2

x=(-10+15)/4=5/4 which is not equal to 2

Hence (2,-2) is not a solution of the given equation.

proved

Answered by lizvalle
14

Answer:

I found three solutions of the equation 4x-5y =15 are (5,1), (10,5), (20,13). Solution set (2, -2) is not solution of the equation.

Step-by-step explanation:

I employed the listing method of the possible values of 4x and subtracted it for possible values of 5y that could give me a result of 15.

20 -5 =15  in equation form, 4(5) -5(1) =15. Thus (5, 1)

40-25 = 15 in equation form, 4(10)-5(5) = 15. Thus (10,5)

80-65 = 15 in equation form, 4(20) - 5(13) =15. Thus (20,13)

To check (2, -2) substitute its value to the equation, 4(2) -5(-2) = 15

8+10 = 15

18 ≠15

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