Question

find two
Solution of the equation at 24
= 7
The class marks of a distribution ante!
47 , 52, 57,62,67, 72, 77, 82, 87, 92, 97, 102
Determine the class interval corresponding to 72
find the value of a
x. if 32x-8
53
225
SH​

Answer 1

Answer:

hope it helps.................

Answer 2

Answer:

class size = difference between two consecutive class marks

therefore clas size=5

lower limit =class mark -class size/2

=44.5

upper limit =class mark +class size /2

=49.5

therefore the class limits are

44.5-49.5

49.5-54.5

54.5-59.5

59.5-64.5

64.5-69.5

69.5-74.5.

hope it helps.....