Find two solution of the equation4x+3y = 12
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Answered by
1
On putting x = 0 in Eq. (i), we get
4(0) +3y =12 ⇒ 3y =12
⇒ y = 12 / 3 = 4
So, (0, 4) is a solution of given equation.
On putting y = 0 in Eq. (i), we get
4x+ 3 (0) =12 ⇒ 4x =12
x = 12 / 4 =3
So, (3, 0) is a solution of given equation.
Hence the two solutions of given equation are (0, 4), (3, 0).
Answered by
1
Answer:
x=3
y=0
Step-by-step explanation:
4(3)+3(0)=12
12+0=12
12=12
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