Question

find two solution of the following equation :2(x+3)-3(y+1)​

Answer 1

2(x-3)-3(y-1) = 0

2x-6-3y+3 = 0

2x-3 -3y =0

2x-3y = 0+3

2x =3+3y

x = 3+3y/2

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solutions are :

==> if we put y = 1

then , x = 3+3(1)/2

x = 6 / 2

x = 3

so x = 3 , y = 1

==> if we put y = 3

then, x = 3+3(3)/2

x = 3+9/2

x = 12/2

x = 6

so, x= 6 ,y = 3

==> if we put y = 5

then, x = 3+3(5)/2

x = 3+15/2

x = 18/2

x = 9

so x= 9, y=5

==> if we put y = 7

then ,x = 3+3(7)/2

x = 3+21/2

x = 24/2

x = 12

so, x = 12 and y= 7

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