Find two solutions for 4x+3y=12
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The equation 4x - 3y = 12 is a linear equation in standard form. When given a linear equation in standard form, we can use its intercepts to graph the line. The xand y intercepts of a line are the points where the graph of the line cross the x-axis and y-axis, respectively. Therefore, y is equal to 0 at the x-intercept, and x is equal to 0 at the y-intercept, so we can find the intercepts by plugging x = 0 or y = 0 into our equation and solving for the other variable. This will give us two points on the line, so all we have to do to graph the line is connect those two intercepts in a straight line.
Consider our equation 4x - 3y = 12. To graph this equation, we simply find the intercepts of the line, plot them, and then connect them in a straight line.
To find the x-intercept, we plug y = 0 into the equation and solve for x.
4x - 3(0) = 124x = 12x = 3
We get that the line crosses the x-axis at x = 3, or at the point (3,0).
To find the y-intercept, we plug x = 0 into the equation and solve for y.
4(0) - 3y = 12-3y = 12y = -4
We get that the line crosses the y-axis at y = -4, or at the point (0,-4).
Now, we just plot our intercepts, (3,0) and (0,-4), and connect them in a straight line.
Consider our equation 4x - 3y = 12. To graph this equation, we simply find the intercepts of the line, plot them, and then connect them in a straight line.
To find the x-intercept, we plug y = 0 into the equation and solve for x.
4x - 3(0) = 124x = 12x = 3
We get that the line crosses the x-axis at x = 3, or at the point (3,0).
To find the y-intercept, we plug x = 0 into the equation and solve for y.
4(0) - 3y = 12-3y = 12y = -4
We get that the line crosses the y-axis at y = -4, or at the point (0,-4).
Now, we just plot our intercepts, (3,0) and (0,-4), and connect them in a straight line.
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