Question

find two solutions for each of the following equation 4x-3y-4=0​

Answer 1

Answer:

4x−3y+4=0

⟹x=

4

−4+3y

Let, y=4, then x=

4

−4+3(4)

=2

Similarly, when y=0,x=−1

4x+3y−20=0

⟹x=

4

20−3y

Let, y=4, then x=

4

20−3(4)

=2

Similarly, when y=0,x=5

Plotting the above points on the graph, we get, the intersecting point i.e(2,4)

Area of the region bounded by these lines and x-axis =

2

1

×6units×4 units

=12 sq. units.

Answer 2

Step-by-step explanation:

SWER

4x−3y+4=0

⟹x=4−4+3y

Let, y=4, then x=4−4+3(4)=2

Similarly, when y=0,x=−1

4x+3y−20=0

⟹x=420−3y

Let, y=4, then x=420−3(4)=2

Similarly, when y=0,x=5

Plotting the above points on the graph, we get, the intersecting point i.e(2,4)

Area of the region bounded by these lines and x-axis =21×6units×4 units

=12 sq. units.