Find two solutions for each of the following equations:
(i) 4x + 3y = 12
(ii) 2x + 5y = 0
(iii) 3y + 4 = 0
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1 4x + 3y = 12
(x,y ) = (3,0)
( x;y)= (0 , 4)
2 2x+ 5y = 0
x and y are 0,0
x and y are 5 and - 2
3 3y+ 4= 0
x and y are (0,0)
x and y are - 1/3
he it is helpful
THANK YOU
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