Question

Find two solutions of √7x +3y=0.​

Answer 1

Answer:

(0,0) (1/√7, -1/3)

Step-by-step explanation:

x=0 => √7(0) +3y=0

=> 0+3y=0 => y=0

(0,0)

Let x=1/√7

=> √7(1/√7) +3y=0

=> 1+3y=0 => 3y=-1 =>y= -1/3

(1/√7, -1/3)

Answer 2

Now putting y value in equation (1)

⇒x+2(2)=5

⇒x=5−4

⇒x=1

x=1,y=2