Find two solutions of following equations :
(i) 4x + 3y = 12
(ii) 2x + 5y = 0
(iii) 3y + 4 = 0
{NCERT MATHS CLASS 9th)
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Answered by
83
HELLO DEAR,
(1)..LET,X=0
WE GET,
3Y=12
Y=4
The solution is(0,4)
and we take,Y=0
WE GET,
4X=12
X=3
ANOTHER SOLUTION IS (3,0)
(2).LET,X=0
WE GET,
5Y=0
Y=0
SOLUTION IS (0,0)
AND
TAKE Y=0
WE GET,
2X=0
X=0
{noth solution is same hence we not get different Solution}
(3).LET X=0
0.X+3Y+4=0
3Y=-4
Y=-4/3
SOLUTION IS (0,-4/3)
and
we take,
Y=1
WE GET,
3Y=-4
Y=-4/3
SOLUTION IS (1,-4/3)
solutions are same
IN fact (K,-4/3)
for all real values of x
I HOPE ITS HELP YOU DEAR,
THANKS
(1)..LET,X=0
WE GET,
3Y=12
Y=4
The solution is(0,4)
and we take,Y=0
WE GET,
4X=12
X=3
ANOTHER SOLUTION IS (3,0)
(2).LET,X=0
WE GET,
5Y=0
Y=0
SOLUTION IS (0,0)
AND
TAKE Y=0
WE GET,
2X=0
X=0
{noth solution is same hence we not get different Solution}
(3).LET X=0
0.X+3Y+4=0
3Y=-4
Y=-4/3
SOLUTION IS (0,-4/3)
and
we take,
Y=1
WE GET,
3Y=-4
Y=-4/3
SOLUTION IS (1,-4/3)
solutions are same
IN fact (K,-4/3)
for all real values of x
I HOPE ITS HELP YOU DEAR,
THANKS
rohitkumargupta:
thanks
Answered by
55
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