Question

Find two solutions of the linear equation ` 2(x + 3) – 3(y + 1) = 0​

Answer 1

2(x + 3) – 3(y + 1) = 0

2x + 6 - 3y - 3 =0

2x - 3y + 3 =0

2x - 3y = -3

To make the process easier, let us first find out what is the value of x when y = 0.

2x = 3y - 3

x = (3y - 3) ÷ 2

If y = 0

x = (3(0) - 3) ÷ 2

x = (0 - 3) ÷ 2

x = -3/2 = -1.5

Now let us go back and check what would be the value of y when x = 0

-3y = -2x - 3

y = (-2x - 3) ÷ -3

If x = 0

y = (-2(0) - 3) ÷ -3

y = (0 - 3) ÷ -3

y = -3/-3

y = 1

So our solutions are (-1.5, 0) and (0, 1)

This method is especially useful to plot graphs easily as given in the attachment.