Question

Find two solutions of the linear equation 2x-3y-12=0?​

Answer 1

answer

2x -3y =12

2y -1 =x

Answer 2

Answer:

2x - 3y - 12 = 0

when x = 3

2 × 3 - 3y - 12 = 0

6 - 3y = 12

-3y = 12 - 6

-3y = 6

y = - 6/3

y = -2

when x = 6

2 × 6 - 3y - 12 = 0

12 - 3y - 12 = 0

12 - 3y = 12

-3y = 12 - 12

y = - 0/3

y = 0

Solutions

1) x = 3

  y = -2

2) x = 6

   y = 0

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