Math, asked by aditya646, 1 year ago

Find two solutions of the linear equation 5x - 4y = -8

Answers

Answered by narendersingh4803
111

Answer:

1)  5x - 4y = - 8

    let x = 0

    so, 5(0)-4y=-8

    0-4y=-8

    y=-8/4

     y=-2

2) 5x-4y=-8

   let y = 1

   5x-4(1)=-8

   5x-4=-8

   5x = -8/4

    5x = -2

    x = -2/5

   

Step-by-step explanation:

Answered by ankhidassarma9
6

Answer:

Two solutions of the linear equation 5x - 4y = -8 are ( x=0,y=2 )  ,

( x= -8/5,y=0 ) .

Step-by-step explanation:

5x - 4y = -8

Using slope-intercept form, which is represented as : y = mx + b ,where

m is the slope of the line, b is the y-intercept, x and y are the coordinates of the x-axis and y-axis.

we can rewrite the given equation as : -4y = -5x -8   0r y=5/4 x + 2;..........(i)

  • If the straight line is parallel to the x-axis, then the x-coordinate will be 0. Therefore, putting x=0 in the equation (i) we will get y=2.

 Hence( x=0,y=2 )  is one solution for the given equation.

  • If the line is parallel to the y-axis, the y-coordinate will be 0.

     Therefore, putting y=0 in the equation (i) we will get

      5/4x + 2 = 0

   or, x=(-2)×4/5 =-8/5

  Hence( x= -8/5,y=0 )  is another solution for the given equation.

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