Math, asked by akhan838218, 2 months ago

find two solutions of the linear equation 7x-3y=5​

Answers

Answered by sensanchita62
2

2] 2y = -3x + 11

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1]

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much :

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1 y = -3x/2+11/2

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1 y = -3x/2+11/2// Use the x value to solve for y

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1 y = -3x/2+11/2// Use the x value to solve for y y = -(3/2)(1)+11/2 = 4

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1 y = -3x/2+11/2// Use the x value to solve for y y = -(3/2)(1)+11/2 = 4 Solution :

2] 2y = -3x + 11 [2] y = -3x/2 + 11/2// Plug this in for variable y in equation [1] [1] 7x - 3•(-3x/2+11/2) = -5 [1] 23x/2 = 23/2 [1] 23x = 23// Solve equation [1] for the variable x [1] 23x = 23 [1] x = 1 // By now we know this much : x = 1 y = -3x/2+11/2// Use the x value to solve for y y = -(3/2)(1)+11/2 = 4 Solution : {x,y} = {1,4}

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Answered by IIMissTwinkleStarII
1

x=1,y=2

x=2,y=1

x=3,y=1

x=1,y=3

x=1,y=2

Given equations are:

x+2y=5      

7x+3y=13    

Multiplying equation (1) by 7

7x+14y=35 ...(3)

Subtracting equation (2) from equation (3),

we have,

11y=22

y=2

Now putting y value in equation (1) 

⇒x+2(2)=5

⇒x=5−4

⇒x=1

x=1,y=2

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