Find twonumbers which differ by 4 and such that one-half of the greater exceeds one-sixth of the less by 8
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Let the two numbers be x and x+4
∴the equation comes out to be
⇒x+4 ÷ 2 = x÷6 + 8
⇒6x + 24 = 2x + 96
⇒4x = 72
⇒x=18
∴the two numbers are
18 and 22
∴the equation comes out to be
⇒x+4 ÷ 2 = x÷6 + 8
⇒6x + 24 = 2x + 96
⇒4x = 72
⇒x=18
∴the two numbers are
18 and 22
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