Math, asked by reetaadhiya79, 11 months ago

find unknown angles​

Attachments:

Answers

Answered by ROCKSTAR1OO8
0

Answer:

We know that

Angles on a semicircle is 90° (eq1)

Now

angleACB = 90°. (using eq1)

y=90°

now

z=60° (vertically opposite angle)

now

let us name the intersection point of z and 60° as E.

now

On the line segment BC

angleAEC + angleAEB = 180° (linear pair)

60°+angleAEB=180°

angleAEB = 120°

In triangle AEB

By using angle sum property,

angleEAB + angleAEB + angleABE =180°

15°+ 120° + x = 180°

x=45°

Hence ans is x=45°,y=90°,z=60°

Similar questions