Question

find using distributive property
a) 987X 1001​

Answer 1

Lets us know the distributive property first :

Let us take three numbers A, B and C.

The distributive property is

A × (B + C) = (A × B) + (A × C).

Now we find the required solution :

Now, 987 × 1001

= 987 × (1000 + 1)

= (987 × 1000) + (987 × 1), using the property

= 987000 + 987

= 987987

Answer 2

Answer:

987 can be written as 1000 - 3

1001 can be written as 1000+1

(1000-3)(1000+1) = (1000)^2 - 3(1000) - 3 (1) + 1000×1

1000000 - 3000-3 + 1000 = 997997

this is done by using this identity

{(x-a)(x+b) = x^2 +-ax -ab + bx }