find using distributivity a){9/10×4/12}+{9/10×-3/9}
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Step-by-step explanation:
Since we have given that
(\dfrac{9}{16}\times \dfrac{4}{12})+(\dfrac{9}{16}\times \dfrac{-3}{9})\\
We have to use the "Distributive law":
a×(b+c)=a×b+a×c
So, it becomes,
\frac{9}{16}(\frac{4}{12}-\frac{3}{9})\\\\=\frac{9}{16}\times (\frac{1}{3}-\frac{1}{3})\\\\=\frac{9}{16}(0})\\\\=0
Hence, Using distributivity, we get 0.
anusuya61:
thank you
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