Question

find using identity (2x+1)^3​

Answer 1

Answer:

Identity: (a+b)^3 = a^3+b^3+3ab( a+b)

(2x)^3 + (1)^3 + 3*2x*1(2x +1)

8x^3 +1+ 6x(2x+1)

8x^3 +1+12x^2 + 6x

ur answer is 8x^3+1+12x^2+6x

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Answer:-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\green{\sf{Find\:Here:-}}}}}}$.

✴$\red{\:Value\:of\:(2x+1)^3}$.

$\large{\underline{\underline{\mathfrak{\pink{\sf{Explanation:-}}}}}}$.

➡We know that ,

✴ $\red{\:(a+b)^3\:=\:(a^3+b^3+3a^2b+3ab^2)}$.

➡Usnig this identity

$\implies\:(2x+1)^3$.

$\implies\:[(2x)^3+1^3+3*(2x)^2(1)+3*(2x)*(1)^2]$.

$\implies\:[8x^3+1+12x^2+6x]$.

$\implies\:[8x^3+12x^2+6x+1]$.

_____________