Question

find value cos60 geometrically

Answer 1

Here's the soln to ur question

Answer 2

Answer:

Step-by-step explanation:

Let ABC be an equilateral triangle whose all the three sides are equal to K. Since, ABC is an equilateral triangle, thus all the angles of the given triangle will be equal to 60°.

Now, draw AD ⊥BC, thus by geometry, AD bisects ∠BAC and also bisects the side BC.

Therefore, in right angled triangle ACD, we have

$cos60^{\circ}=\frac{CD}{AC}=\frac{\frac{K}{2}}{K}=\frac{1}{2}$

Thus, the value of $cos60^{\circ}$ is $\frac{1}{2}$.