find value k 3x²+(2k+1)x-7
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The given equation kx2 + 4x + 1 = 0 is in the form of ax2 + bx + c = 0
Where a = k, b = 4, c = 1
For the equation to have real and equal roots, the condition is
D = b2 – 4ac = 0
⇒ 42 – 4(k)(1) = 0
⇒ 16 – 4k = 0
⇒ k = 4
The value of k is 4.
(ii) kx2 – 2√5x + 4 = 0
Step-by-step explanation:
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