Math, asked by MadhurVatsal, 1 year ago

Find value of 0.42323232323..........(QUESTION OF GP)​

Answers

Answered by Anonymous
15

SOLUTION:

Let the given value be some variable let say x.

 x = 0.4232323...

Can be written as,

x = 0. 4\overline{23}

Can also be expressed as,

{x = 0.4 + (0.023 + 0.00023 + 0.0000023 + ...)}

Now, we can observe that the series in the bracket is forming an infinite GP where first term is 0.023 and the common ratio is 1/100 or 0.01.

We have formula for sum of infinite GP.

  \boxed{S_\infty  =   \frac{a}{1 - r}}

Note: In an infinite GP, common ratio lies between the internal (0, 1) otherwise the series will diverge.

By using the formula, we get:

{x = 0.4 + \left ( \dfrac{0.023}{1 -  \frac{1}{100}}  \right)}

{x = 0.4 + \left ( \dfrac{ \frac{23}{1000} }{  \frac{99}{100}}  \right)}

{x = 0.4 +\dfrac{23}{990}}

{x =  \dfrac{4}{10} +\dfrac{23}{990}}

{x =  \dfrac{396 + 23}{990}}

{x =  \dfrac{419}{990}}

x =  \dfrac{313}{495}

This is the required answer.

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