find value of [119]²+[119][111]+[111]²/[119]³-[111]³
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let 119 = a and 111 = b
(a² + ab + b²)/(a³ - b³)
= (a² + ab + b²)/{(a - b)(a² + b² + ab)} {a³ - b³ = (a - b)(a² + ab + b²)}
= 1/(a - b)
= 1/8
(a² + ab + b²)/(a³ - b³)
= (a² + ab + b²)/{(a - b)(a² + b² + ab)} {a³ - b³ = (a - b)(a² + ab + b²)}
= 1/(a - b)
= 1/8
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