Question

find value of 216 a cube -343 cube when 6a-7b=11 ab=8 by using formula a (cube) + b (cube) = (a+b) {(a square - ab + b square }​

Answer 1

Answer:

$\sqrt[3]216 = 6$

$\sqrt[3]343 = 7$

$a ^3 + b ^3 = (a + b)(a {}^{2} \: - \: ad \: + \: d {}^{2} )$