Question

Find value of (2²) ²​

Answer 1

$\tt(2 {}^{2} ) {}^{2} \\ \tt = 2 {}^{4} \\ \tt = 2 \times 2 \times 2 \times 2 \\ \tt = 16$

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Answer 2

Answer:

$16$ is the value of $2^4$.

Step-by-step explanation:

Explanation:

From the question, we need to find out the value of $(2^2)^2$.

Rule for exponents:

• Basically, all that is required is to multiply the powers. Given that powers, exponents, and indices are all the same thing, this is also known as the exponent bracket rule or the indices bracket rule.

• When an exponent appears outside of parentheses, the entire amount is increased to that power.

• In other words, the amount enclosed in parenthesis is multiplied by itself however many times the exponent on the outside indicates.

• $(a^m)^n$  = $a^{mn}$ is the power rule for exponents. Multiply the exponent by the power to raise a number with an exponent to that power.

Step 1:

We have, $(2^2)^2$

According to the exponent rule;

⇒$(2)^{2.2}$ = $2^4$

⇒ $2^4$ = 2.2.2.2= 16

Final answer:

Hence, 16 is the value of $2^4$.

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