find value of (√3+1)4-(√3-1)4
Answers
Answered by
0
Answer:
I hope it helpful to you.
Step-by-step explanation:
[
4
C
0
(
3
)
4
(1)
0
+
4
C
1
(
3
)
3
(1)
1
+
4
C
2
(
3
)
2
(1)
2
+
4
C
3
(
3
)
1
(1)
3
+
4
C
4
(
3
)
0
(1)
4
]+[
4
C
0
(
3
)
4
(−1)
0
+
4
C
1
(
3
)
3
(−1)
1
+
4
C
2
(
3
)
2
(−1)
2
+
4
C
3
(
3
)
1
(−1)
3
+
4
C
4
(
3
)
0
(−1)
4
]
=(
3
)
4
+4(
3
)
3
+6(
3
)
2
+4(
3
)+1+(
3
)
4
−4(
3
)
3
+6(
3
)
2
−4(
3
)+1
=2(
3
)
4
+12(
3
)
2
+2
=56
Answered by
1
answer
(3+1)4+(3−1)4
Using binomial expansion
=[4C0(3)4(1)0+4C1(3)3(1)1+4C2(3)2(1)2+4C3
(3)1(1)3+4C4(3)0(1)4]+[4C0(3)4(−1)0+4C1(3)
p
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