Question

Find value of 4x^2+y^2+4xy-10yz-20zx when x=4 y=3 and z=2

Answer 1

Answer:

$4x { }^{2} + y {}^{2} + 4xy - 10yz - 20zx \\ putting \: the \: value \: of \: x \: y \: and \: z \: in \: the \: equation \\ 4 \times 4 {}^{2} + 3 {}^{2} + 4 \times 4 \times 3 - 10 \times 3 \times 2 - 20 \times 2 \times 4 \\ 64 + 9 + 48 - 60 \\ 121 - 60 \\ 61$

hey mate!!

here is your answer