Question

Find value of [6^-1+(3/2)^-1]^-2​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\sf \Large Solution!!$

$\sf \to [6^{-1}+(\frac{3}{2})^{-1}]^{-2}$

$\sf \to [\frac{1}{6}+\frac{2}{3}]^{-2}$

$\sf \to [\frac{5}{6}]^{-2}$

$\sf \to (\frac{6}{5})^{2}$

$\sf \to \frac{36}{25}$

$\sf \to 1\frac{11}{25}$