Question

find value of A (0°<A°<90°) if cos 63° sec (90-A) = 1. it's urgent please answer. don't spam. spams will be Reported.​

Answer 1

$\bold\red {ANSWER}$

cos 63° sec(90°-θ)=1

⇒cos 63° cosec θ=1

⇒ cos 63°=sin θ

⇒ cos 63°=cos (90°-θ)

⇒ 63°=90°-θ

⇒θ=27°

Therefore, the value of the variable is 27.