Math, asked by nikitasinghmar46, 10 months ago

Find value of a and b
√3-1 / √3+1 =a+b√3

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Answers

Answered by sandy1816
1

Step-by-step explanation:

3-1/3+1=a+b3

(3-1)/(3)²-1=a+b3

3+1-23/3-1=a+b3

4-23/2=a+b3

2-3=a+b3

a=2 b=-1

Answered by Anonymous
0

\huge{\underline{\underline{\purple{♡Solution→}}}}

 \frac{ \sqrt{3} - 1 }{ \sqrt{3}  + 1}  = a + b \sqrt{3}

Divide and multiply by 3 - 1

 \frac{ \sqrt{3} - 1 }{ \sqrt{3}  + 1}  \times  \frac{ \sqrt{3} - 1 }{ \sqrt{3}   - 1} = a + b \sqrt{3}

 \frac{ {( \sqrt{3} - 1) }^{2} }{ { \sqrt({3}) }^{2}  - 1}  = a + b \sqrt{3}

 \frac{3   + 1 - 2 \sqrt{3} }{3 - 1}  = a +  \sqrt{3}

 \frac{4 - 2 \sqrt{3} }{2}  = a + b \sqrt{3}  \\  \frac{2(2 -  \sqrt{3} )}{2}  = a + b \sqrt{3} \\ 2 -  \sqrt{3 }  = a + b \sqrt{3} \:

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