Question

find value of a and b​

Answer 1

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$\frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} \\ \\ = \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1 } \\ \\ = \frac{ {( \sqrt{3} - 1)}^{2} }{ { \sqrt{(3)} }^{2} - {(1)}^{2} } \\ \\ = \frac{3 + 1 - 2 \sqrt{3} }{3 - 1} \\ \\ = \frac{4 - 2 \sqrt{3} }{2} \\ \\ = 2 - \sqrt{3} \\ answer.. \\ a = 2 \\ b = 1$

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