find value of a and b so that 2x4-3x3-4x2+ax+b is divisible by x2+1
Answers
Answered by
0
Given : 2x⁴-3x³-4x²+ax+b is divisible by x²+1
To Find : Values of a and b
Solution:
divisible by x²+1
=> x² = - 1
=> x = ± i
2x⁴-3x³-4x²+ax+b
x = i
=> 2(i)⁴ - 3(i)³-4(i)²+ai+b = 0
=> 2 + 3i + 4 + ai + b = 0 (∵ i⁴ = 1 , i³ = -i and i² = - 1)
=> (a + 3)i + (b + 6) = 0
Equating real and imaginary parts
=> a =-3 b = - 6
Learn More:
on dividing x3-3x2+x+2 by a polynomial g(x),the quotient and ...
brainly.in/question/3135153
Divide 9x^3+3x^2-5x+7 by (3x-1) write the quotient and remainder ...
brainly.in/question/6190809
Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1 ...
brainly.in/question/4743553
Similar questions