FIND VALUE OF a, b, c
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Hi ,
LHS = 4/( 2 + √3 + √7 )
= 4( 2 + √3 - √7)/[(2+√3+√7)(2+√3-√7)]
=4(2+√3-√7)/[ (2 + √3 )² - ( √7 )² ]
= 4( 2 + √3 - √7 )/ ( 4 + 3 +4√3 - 7 )
= 4( 2 +√3 - √7 )/4√3
= ( 2 + √3 - √7 )/√3
= [ √(4/3 ) + 1 - √( 7/3 )
= 1 + √(4/3 ) - √(7/3 )-----( 1 )
= √a + √b - √c ---( 2 )
compare ( 1 ) and ( 2 ) , we get
a = 1 , b = 4/3 , c = 7/3
I hope this helps you.
: )
LHS = 4/( 2 + √3 + √7 )
= 4( 2 + √3 - √7)/[(2+√3+√7)(2+√3-√7)]
=4(2+√3-√7)/[ (2 + √3 )² - ( √7 )² ]
= 4( 2 + √3 - √7 )/ ( 4 + 3 +4√3 - 7 )
= 4( 2 +√3 - √7 )/4√3
= ( 2 + √3 - √7 )/√3
= [ √(4/3 ) + 1 - √( 7/3 )
= 1 + √(4/3 ) - √(7/3 )-----( 1 )
= √a + √b - √c ---( 2 )
compare ( 1 ) and ( 2 ) , we get
a = 1 , b = 4/3 , c = 7/3
I hope this helps you.
: )
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