Question

find value of a , please help​

Answer 1

Answer:

by factor theorem

3(2)-2a = 0

6=2a

a=3

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Answer 2

Step-by-step explanation:

QUESTION:

If (x-2) is one of the factor of (3x-2a), then find the value of a.

SOLUTION:

If x-2=0

Then, x=2

∴ $f(x)$= 3x-2a

=> $f(</em><em>2</em><em>)$= 3×2-2a

=> $f(</em><em>2</em><em>)$= 6-2a ………… (i)

Since, (x-2) is a factor of polynomial $f(x)$, so it is equal to 0.

BTP,

6-2a = 0

=> -2a = -6

=> 2a = 6

=> a = 3

HENCE, the value of a is 3.